What is the vertex form of 4x^2+4x-12

(-0.5, - 13)

(-1/2, - 13/4)

Step-by-step explanation:

Start with y = 4x^2+4x-12. Put this into the form y = a (x-h) ^2 + k, where (h, k) represents the vertex.

Factor 4 out of this expression, obtaining: y = 4 (x^2 + x - 3).

Next, complete the square of the quantity inside parentheses:

y = 4[ x^2 + x + 1/4 - 1/4 - 3 ], or

y = 4[ (x + 1/2) ^2 - 13/4 ]

We can now conclude that the vertex is (-1/2, - 13/4).