A 6-foot man walks on level ground toward a 60 foot flag pole. He notes different angles of elevation θ to the top of the pole when he is different horizontal distances x away from the pole.

a) Express the man's horizontal distance from the base of the pole x (in feet) as a function of the angle of elevation θ in degrees. Type theta for θ.

b) Express the angle of elevation θ as a function of the man's horizontal distance to the base of the pole x.

Question

Cade Mayer

Mathematics

23 March, 18:24

A 6-foot man walks on level ground toward a 60 foot flag pole. He notes different angles of elevation θ to the top of the pole when he is different horizontal distances x away from the pole.

a) Express the man's horizontal distance from the base of the pole x (in feet) as a function of the angle of elevation θ in degrees. Type theta for θ.

b) Express the angle of elevation θ as a function of the man's horizontal distance to the base of the pole x.

+4

Answers (1)

Know the Answer?

Aliya Guerra · Answer 1

a) x = 54/tan (theta)

b) theta = arctan (54/x)

Step-by-step explanation:

a) The tangent ratio is the ratio of the side opposite an acute angle in a right triangle to the adjacent side. For the angle of elevation, the adjacent side is the distance x to the flagpole. The side opposite is the 54-foot difference between the top of the man's head and the top of the flagpole. So, we have ...

tan (theta) = 54/x

Solving for x gives ...

x = 54/tan (theta)

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b) Solving the first equation in the previous part for theta involves the inverse tangent function:

theta = arctan (54/x)