Sonya had 20 minutes to do a three-problem quiz. She spent 10 9 10 minutes on question A and 6 3 5 minutes on question B. How much time did she have left for question C?

Question

Larsen

Mathematics

13 March, 20:09

Sonya had 20 minutes to do a three-problem quiz. She spent 10 9 10 minutes on question A and 6 3 5 minutes on question B. How much time did she have left for question C?

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Answers (1)

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Fido · Answer 1

Answer: she has 2 5/10 minutes left for question C

Step-by-step explanation:

Total time that Sonya has for the three-problem quiz is 20 minutes.

She spent 10 9/10 minutes on question A. Converting 10 9/10 minutes to improper fraction, it becomes 109/10 minutes.

She spent 6 3/5 minutes on question B. Converting 6 3/5 minutes to improper fraction, it becomes 33/5 minutes.

Total time spent on question A and question B is

109/10 + 33/5 = (109 + 66) / 10

= 175/10 minutes

The amount of time that she has left for question C would be

20 - 175/10 = (200 - 175) / 10

= 25/10 = 2 5/10 minutes