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11 January, 15:46

Does there exist a Pythagorean triple of the form m, m+7, and m+8, where m is a natural number? If the answer is yes, determine all such Pythagorean triples. If the answer is no, prove that no such Pythagorean triple exists.

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  1. 11 January, 16:15
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    Yes, m = 5

    Step-by-step explanation:

    m^2 + (m+7) ^2 = (m+8) ^2 by Pythagorean Theorem. You get m = 5, - 3 so m = 5 since - 3 is not a natural number.
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