Scientific research on popular beverages consisted of 70 studies that were fully sponsored by the food industry, and 30 studies that were conducted with no corporate ties. Of those that were fully sponsored by the food industry, 15 % of the participants found the products unfavorable, 23 % were neutral, and 62 % found the products favorable. Of those that had no industry funding, 38 % found the products unfavorable, 16 % were neutral, and 46 % found the products favorable. a. What is the probability that a participant selected at random found the products favorable?

b. If a randomly selected participant found the product favorable, what is the probability that the study was sponsored by the food industry?

c. If a randomly selected participant found the product unfavorable, what is the probability that the study had no industry funding?

Question

Xzavier Roth

Mathematics

13 August, 05:57

Scientific research on popular beverages consisted of 70 studies that were fully sponsored by the food industry, and 30 studies that were conducted with no corporate ties. Of those that were fully sponsored by the food industry, 15 % of the participants found the products unfavorable, 23 % were neutral, and 62 % found the products favorable. Of those that had no industry funding, 38 % found the products unfavorable, 16 % were neutral, and 46 % found the products favorable. a. What is the probability that a participant selected at random found the products favorable?

b. If a randomly selected participant found the product favorable, what is the probability that the study was sponsored by the food industry?

c. If a randomly selected participant found the product unfavorable, what is the probability that the study had no industry funding?

+1

Answers (1)

Know the Answer?

Humberto Villa · Answer 1

a. 0.26

b. 0.7

c. 0.38

Step-by-step explanation:

For a)

For sponsored studies: 62 % found the products favorable. The percentage is 0.62.

For non-sponsored studies 46% found the products favorable. The percentage is 0.46

Total probability = P (A) * P (B)

= 0.46 * 0.62

= 0.2604

For b)

Probability for the food industry = 0.7

For c) 1 - (0.62) = 0.38