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14 March, 03:13

The greater of two numbers is six more than 4 times the smaller. Their sum is 41. Find the number

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  1. 14 March, 03:29
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    smaller number is 7

    larger number is 35

    Step-by-step explanation:

    Let the smaller number be x

    Given that greater number is 6 more than 4 times the smaller number.

    If x is value of smaller number then 4 times the smaller number is 4*x = 4x

    six more than 4 times the smaller number will be 6+4x.

    Thus larger number is 6+4x

    Sum of smaller and larger no is 41.

    Substituting the value of smaller and larger number in sum we have

    x+6+4x = 41

    => 5x+6 = 41

    => 5x = 41-6

    => 5x = 35

    =>x = 35/5 = 7

    Thus smaller number is x = 7

    larger number = 4x+6 = 4*7+6 = 35
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