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22 July, 03:22

For a school field trip the students had two options for lunch, a turkey or egg salad sandwich, so it is impossible for a student have both lunches. If the probability that a student chooses a turkey sandwich is 0.10, and the probability that a student chooses an egg salad sandwich is 0.67, what is the probability that a student chooses a turkey or egg salad sanwich?

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  1. 22 July, 03:49
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    Answer: 0.77

    Step-by-step explanation:

    Given : Probability that a student chooses a turkey sandwich is

    P (Turkey) = 0.10

    Probability that a student chooses an egg salad sandwich is

    P (egg salad) = 0.67

    Also, it is impossible for a student have both lunches.

    ∴ P (Turkey and egg salad) = 0

    Now, the probability that a student chooses a turkey or egg salad sandwich will be

    P (Turkey or egg salad) = P (Turkey) + P (egg salad) - P (Turkey and egg salad)

    = 0.10 + 0.67-0 = 0.77

    Hence, the probability that a student chooses a turkey or egg salad sandwich = 0.77
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