A rancher has a rectangular 40 acre piece of property fronting a highway. He wants to put a barbed-wire fence along his road frontage. How much fence does he need if his property depth is 1,200'?

Question

Dawson Daniels

Mathematics

31 August, 21:03

A rancher has a rectangular 40 acre piece of property fronting a highway. He wants to put a barbed-wire fence along his road frontage. How much fence does he need if his property depth is 1,200'?

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Answers (1)

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Darion Gilmore · Answer 1

An acre is a surface measure, used in agriculture in several countries.

According to the country and the time, it is equivalent to several surfaces.

We will use the following conversion:

1 acre = 43560 feet ^ 2

Thus:

40 acre = 1,742,400 feet ^ 2

The area of the rectangle is:

1,742,400 = (1,200) * (x)

Clearing the other dimension we have:

x = (1742400) / (1200)

x = 1452 feet

Answer:

He needs 1452 feet of fence.