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Irvin Burgess
Mathematics
19 December, 19:28
Whatfour consecutive integers have a sum of 90
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Beck
19 December, 19:38
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N + (n+1) + (n+2) + (n+3) = 90
if n is the first number, then the next number is 1 more than n, the next number is 2 more than n, etc.
Simplify the above expression:
4n + 6 = 90
4n = 84
n = 21
n+1 = 22
n+2 = 23
n+3 = 24
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