Whatfour consecutive integers have a sum of 90

N + (n+1) + (n+2) + (n+3) = 90

if n is the first number, then the next number is 1 more than n, the next number is 2 more than n, etc.

Simplify the above expression:

4n + 6 = 90

4n = 84

n = 21

n+1 = 22

n+2 = 23

n+3 = 24