In a tornado the wind velocity in meters per second can be described by the function v (p) = 12.3 sqrt 1134-3p where 'p' is th air pressure in millibars. What is the air pressure of a tornado in which the wind velocity is 49.3 meters per second?

We are given with the function

v (p) = 12.3 √ (1134 - 3p)

We are asked to find the air pressure when the velocity is 49.3 m/s

Substituting this to v (p)

49.3 = 12.3 √ (1134 - 3p)

49.3/12.3 = √ (1134 - 3p)

4.01 = √ (1134 - 3p)

4.01² = √ (1134 - 3p) ²

16.07 = 1134 - 3p

3p = 1134 - 16.07

3p = 1117.92

p = 1117.92/3

p = 372.64 millibars