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1 February, 16:37

What are the roots of x2 + 8x - 48 = 0?

show me the work

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  1. 1 February, 16:58
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    x^2 + 8x - 48 = 0

    That is a quadratic equation where

    a = 1

    b = 8

    c = - 48

    We can solve it by using the quadratic formula:

    x = [-b + - sq root (b^2 - 4ac) ] / 2a

    x = [-8 + - sq root (64 - 4*1*-48) ] / 2*1

    x = [-8 + - sq root (256) ] / 2

    x = [-8 + - 16] / 2

    x1 = 8 / 2 = 4

    x2 = - 24 / 2 = - 12
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