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Rhett Salazar
Mathematics
23 August, 18:54
In algibratic fractions what is 1/2x-1/3y
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Amiga
23 August, 19:02
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1 - 1 = 1 (2x) (3y) - 1 (2x) (3y) = 6xy - 6xy = 0
2x 3y (2x) (3y) (2x) (3y) 6xy 6xy 6xy
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Savanah
23 August, 19:04
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Simplify each term.
1/2X - 1/3Y
Combine 1/2x and - 1/3y using a common denominator.
To write - 1/3y as a fraction with a common denominator, multiply by 2x/2x.
(1 / 2x) (3y / 3y) + (-1 / 3y) (2x / 2x)
Write each expression with a common denominator of 6xy, by
multiplying each by an appropriate factor of 1.
1 (3y) / 6xy - 1 (2x) / 6xy
Combine the numerators over the common denominator.
1 (3y) - (1 (2x)) / 6xy
Simplify the numerator.
3y - (1 (2x)) / 6xy
Simplify.
3y - (2x) / 6xy
3y-2x / 6xy
Simplify with factoring out.
Reorder 3y and - 2x.
-2x+3y / 6xy
Factor - 1 out of - 2x.
-1 (2x) + 3y / 6xy
Factor - 1 out of 3y.
-1 (2x) - 1 (-3y) / 6xy
Factor - 1 out of - 1 (2x) - 1 (-3y).
-1 (2x-3y) / 6xy
Move the negative in front of the fraction.
- 2x-3y / 6xy
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