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23 August, 18:54

In algibratic fractions what is 1/2x-1/3y

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  1. 23 August, 19:02
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    1 - 1 = 1 (2x) (3y) - 1 (2x) (3y) = 6xy - 6xy = 0

    2x 3y (2x) (3y) (2x) (3y) 6xy 6xy 6xy
  2. 23 August, 19:04
    0
    Simplify each term.

    1/2X - 1/3Y

    Combine 1/2x and - 1/3y using a common denominator.

    To write - 1/3y as a fraction with a common denominator, multiply by 2x/2x.

    (1 / 2x) (3y / 3y) + (-1 / 3y) (2x / 2x)

    Write each expression with a common denominator of 6xy, by

    multiplying each by an appropriate factor of 1.

    1 (3y) / 6xy - 1 (2x) / 6xy

    Combine the numerators over the common denominator.

    1 (3y) - (1 (2x)) / 6xy

    Simplify the numerator.

    3y - (1 (2x)) / 6xy

    Simplify.

    3y - (2x) / 6xy

    3y-2x / 6xy

    Simplify with factoring out.

    Reorder 3y and - 2x.

    -2x+3y / 6xy

    Factor - 1 out of - 2x.

    -1 (2x) + 3y / 6xy

    Factor - 1 out of 3y.

    -1 (2x) - 1 (-3y) / 6xy

    Factor - 1 out of - 1 (2x) - 1 (-3y).

    -1 (2x-3y) / 6xy

    Move the negative in front of the fraction.

    - 2x-3y / 6xy
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