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13 January, 00:42

What's the solution to |1x-12| < 15

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  1. 13 January, 01:01
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    Start with |1x - 12| < 15. Add 12 to both sides. Then |1x - 12 + 12| < 15 + 12

    Simplifying, |x| < 27. Then the two solutions are x - 27. In words, the solution set is the set of all x greater than - 27 and less than + 27.
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