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Yadira Cisneros
Mathematics
4 November, 01:54
Tan [x-pi/4] = tanx - 1
+1
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1
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Jaydin Marsh
4 November, 02:18
0
Solve for x:
-tan (π/4 - x) = tan (x) - 1
Subtract tan (x) - 1 from both sides:
1 - tan (π/4 - x) - tan (x) = 0
Simplify and substitute y = - tan (x).
1 - tan (π/4 - x) - tan (x) = (-tan (x) (1 - tan (x))) / (-tan (x) - 1)
= (y (y + 1)) / (y - 1):
(y (y + 1)) / (y - 1) = 0
Multiply both sides by y - 1:
y (y + 1) = 0
Split into two equations:
y = 0 or y + 1 = 0
Substitute back for y = - tan (x):
-tan (x) = 0 or y + 1 = 0
Multiply both sides by - 1:
tan (x) = 0 or y + 1 = 0
Take the inverse tangent of both sides:
x = π n_1 for n_1 element Z
or y + 1 = 0
Subtract 1 from both sides:
x = π n_1 for n_1 element Z
or y = - 1
Substitute back for y = - tan (x):
x = π n_1 for n_1 element Z
or - tan (x) = - 1
Multiply both sides by - 1:
x = π n_1 for n_1 element Z
or tan (x) = 1
Take the inverse tangent of both sides:
Answer: x = π n_1 for n_1 element Z or x = π n_2 + π/4 for n_2 element Z
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