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18 December, 02:01

5. (x^3y^2) ^4 a) x^12 y^8 b) x^7 y^6 c) (xy) ^20 d) (xy) ^13

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  1. 18 December, 02:24
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    (x^3y^2) ^4 = x^ (3 x 4) y^ (2 x 4) = x^12 y^8
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