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19 July, 21:46

find three consecutive odd integers such that the product of the first and third is 71 more than 10 times the second

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  1. 19 July, 22:14
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    13, 15, 17

    Step-by-step explanation:

    x (x + 4) = 10 (x + 2) + 71

    x2 + 4x = 10x + 20 + 71

    x2 - 6x - 91 = 0

    (x + 7) (x - 13) = 0

    x + 7 = 0

    x = - 7

    -7, - 5, - 3

    x - 13 = 0

    x = 13

    13, 15, 17
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