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30 December, 05:21

The floor of the gazebo shown is a regular octagon. Each side of the floor is 8 feet, and the area is about 309 square feet. You build a small model gazebo in the shape of a regular octagon. The perimeter of the floor of the model gazebo is 7 feet. Find the area of the floor of the model gazebo to the nearest hundredth of a square foot. What is the ratio of the perimeters (in feet) of the real gazebo floor to the model gazebo floor?

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  1. 30 December, 05:24
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    Area: 3.7 ft²

    Ratio: 73.14 : 1

    Step-by-step explanation:

    Perimeter of an octagon = 8*side

    Replacing with perimeter = 7 ft:

    7 = 8*side

    side = 7/8 ft = 0.875 ft

    that is, each side of the model is 7/8 ft length.

    Area of an octagon = 2 * (1 + √2) * side²

    Area of an octagon = 2 * (1 + √2) * (7/8) ²

    Area of an octagon = 3.7 ft²

    Perimeter of real gazebo = 8*8 = 64 ft

    Then, the ratio of the perimeters (in feet) of the real gazebo floor to the model gazebo floor is 64:0.875. Multiplying each term by 8/7, we get 73.14:1
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