What is the positive root of the equation x 2 + 5x = 150? a0

Solution for x^2+5x=150 equation:

Simplifying x2 + 5x = 150 Reorder the terms: 5x + x2 = 150 Solving 5x + x2 = 150 Solving for variable 'x'. Reorder the terms: - 150 + 5x + x2 = 150 + - 150 Combine like terms: 150 + - 150 = 0 - 150 + 5x + x2 = 0 Factor a trinomial. (-15 + - 1x) (10 + - 1x) = 0 Subproblem 1Set the factor ' (-15 + - 1x) ' equal to zero and attempt to solve: Simplifying - 15 + - 1x = 0 Solving - 15 + - 1x = 0 Move all terms containing x to the left, all other terms to the right. Add '15' to each side of the equation. - 15 + 15 + - 1x = 0 + 15 Combine like terms: - 15 + 15 = 0 0 + - 1x = 0 + 15 - 1x = 0 + 15 Combine like terms: 0 + 15 = 15 - 1x = 15 Divide each side by '-1'. x = - 15 Simplifying x = - 15 Subproblem 2Set the factor ' (10 + - 1x) ' equal to zero and attempt to solve: Simplifying 10 + - 1x = 0 Solving 10 + - 1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + - 10 + - 1x = 0 + - 10 Combine like terms: 10 + - 10 = 0 0 + - 1x = 0 + - 10 - 1x = 0 + - 10 Combine like terms: 0 + - 10 = - 10 - 1x = - 10 Divide each side by '-1'. x = 10 Simplifying x = 10Solutionx = {-15, 10}