A cash register contains $10 bills and $20 bills with a total value of $340. If there are 23 bills total then how many of each does the register contain?

12 bills of $10 and 11 bills of $20.

because 12*10 = 120 and 11*20 = 220

add 120+220=340

have a good day

Answer: So there are 12 bills of $10 and 11 bills of $20.

Step-by-step explanation:We are given that the cash register contains $10 and $20 bills.

Let us say there are x number of $10 bills and y number of $20 bills.

So there are total 23 bills.

... (1)

... (2)

We are also given that the total value of bills is $340.

So that gives us the second equation,

... (3)

Plugging the value of x from equation (2) in (3),

y=11

Plugging this value of y back in equation (2),

x=23-11 = 12