A pass code contains 6 digits. The first 3 digits of the code are all even (2,4,6, or 8) and the last 3 are all odd (1,3,5,7, or 9). If digits can be used more than once, how many possible codes are there?

Question

Johan

Mathematics

28 October, 21:32

A pass code contains 6 digits. The first 3 digits of the code are all even (2,4,6, or 8) and the last 3 are all odd (1,3,5,7, or 9). If digits can be used more than once, how many possible codes are there?

+5

Answers (1)

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Jimmy Schwartz · Answer 1

8000

Step-by-step explanation:

The first 3 digits each have 4 options.

The last 3 digits each have 5 options.

The number of possible codes is:

4 * 4 * 4 * 5 * 5 * 5

= 4³ * 5³

= 8000