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28 October, 21:32

A pass code contains 6 digits. The first 3 digits of the code are all even (2,4,6, or 8) and the last 3 are all odd (1,3,5,7, or 9). If digits can be used more than once, how many possible codes are there?

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  1. 28 October, 21:56
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    8000

    Step-by-step explanation:

    The first 3 digits each have 4 options.

    The last 3 digits each have 5 options.

    The number of possible codes is:

    4 * 4 * 4 * 5 * 5 * 5

    = 4³ * 5³

    = 8000
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