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30 April, 18:01

How do I demonstrate that the digits of a perfect square cannot add up to 2,3,5,6, or8?

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  1. 30 April, 18:13
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    2^2=4

    3^2=9

    4^2=16 (1+6=7)

    5^2=25 (2+5=7)

    6^2=36 (3+6=9)

    7^2=49 (4+9=13)

    and so on and so forth.
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