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30 August, 16:10

The probability that an individual is left-handed is 0.12. in a class of 39 students, what is the probability of finding five left-handers

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  1. 30 August, 16:21
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    We are given:

    p = probability = 0.12

    n = total students = 39

    x = left handers = 5

    u = mean = p * n = 4.68

    σ = standard dev = √ (n*p * (1-p)) = √ (39 * 0.12 * 0.88) = 2.03

    Calculating for the z score:

    z = (x - u) / σ

    z = (5 - 4.68) / 2.03

    z = 0.1576 = 0.16

    Using the standard tables for z, the p value is:

    p value = 0.5636 = 56.36%

    Hence there is a 56.36% chance.
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