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25 March, 08:43

The price of Stock A at 9 a. m. was $15.75. Since then, the price has been increasing at the rate of $0.05 per hour. At noon, the price of Stock B was $16.53. It begins to decrease at the rate of $0.13 per hour. If the stocks continue to increase and decrease at the same rates, in how many hours will the prices of the stocks be the same?

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Answers (2)
  1. 25 March, 08:52
    0
    In approximately 3 hours time stock A will be the same price with Stock B

    Step-by-step explanation:

    Stock A increases at $ 0.05 per hour

    stock A at 9 a. m = $ 15.75

    stock A at 12 noon = $ 15.75 + $ 0.05 * 3

    = $ 15.75 + $ 0.15 = $ 15.90

    stock A in the next three hours again will be = $ 15.90 + $ 0.05 * 3

    = $15.90 + $ 0.15 = $ 16.05

    Stock B at 12 noon = $ 16.53

    stock B decreases at $ 0.13 per hour so in the next three hours stock B will be

    = $ 16.53 - $ 0.13 * 3

    = $ 16.53 - $0.39 = $16.14
  2. 25 March, 09:11
    0
    Answer: 3.5
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