The price of Stock A at 9 a. m. was $15.75. Since then, the price has been increasing at the rate of $0.05 per hour. At noon, the price of Stock B was $16.53. It begins to decrease at the rate of $0.13 per hour. If the stocks continue to increase and decrease at the same rates, in how many hours will the prices of the stocks be the same?

Question

Siena Wallace

Mathematics

25 March, 08:43

The price of Stock A at 9 a. m. was $15.75. Since then, the price has been increasing at the rate of $0.05 per hour. At noon, the price of Stock B was $16.53. It begins to decrease at the rate of $0.13 per hour. If the stocks continue to increase and decrease at the same rates, in how many hours will the prices of the stocks be the same?

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Answers (2)

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Matilda Mcclure · Answer 1

In approximately 3 hours time stock A will be the same price with Stock B

Step-by-step explanation:

Stock A increases at $ 0.05 per hour

stock A at 9 a. m = $ 15.75

stock A at 12 noon = $ 15.75 + $ 0.05 * 3

= $ 15.75 + $ 0.15 = $ 15.90

stock A in the next three hours again will be = $ 15.90 + $ 0.05 * 3

= $15.90 + $ 0.15 = $ 16.05

Stock B at 12 noon = $ 16.53

stock B decreases at $ 0.13 per hour so in the next three hours stock B will be

= $ 16.53 - $ 0.13 * 3

= $ 16.53 - $0.39 = $16.14

Curtis Walters · Answer 2

Answer: 3.5