Find 3 consecutive integers such that the smallest is ten less than twice the greatest

Question

Guest

Mathematics

19 April, 23:33

Find 3 consecutive integers such that the smallest is ten less than twice the greatest

+3

Answers (1)

Know the Answer?

Leanna · Answer 1

Let the integers be x, x+1, x+2

Now the smallest is ten less than twice the greatest

So (x+2) 2-10=x

2x+4-10=x

2x-x-6=0

x-6=0

x = 6

The integers then are;

6, 7, 8