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14 January, 22:10

N (n - 4) + n (n + 8) = n (n - 13) + n (n + 1) + 16

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Answers (2)
  1. 14 January, 22:21
    0
    N^2 - 4n + n^2 + 8n = n^2 - 13n + n^2 + n + 16

    -4n + 8n = - 13n + n + 16

    -4n = - 12n + 16

    4n + 12n = 16

    16 = 16

    n = 1
  2. 14 January, 22:33
    0
    n = 1

    Step-by-step explanation:

    n (n - 4) + n (n + 8) = n (n - 13) + n (n+1) + 16

    n^2 - 4n + n^2 + 8n = n^2 - 13n + n^2 + n + 16

    n^4 + 4n = n^4 - 12n + 16

    n^4 - n^4 + 4n + 12n - 16 = 0

    16n - 16 = 0

    16n = 16

    n = 16/16

    n = 1

    better check this ...

    1 (1 - 4) + 1 (1 + 8) = 1 (1 - 13) + 1 (1 + 1) + 16

    1 (-3) + 1 (9) = 1 (-12) + 1 (2) + 16

    -3 + 9 = - 12 + 2 + 16

    6 = 4 + 2

    6 = 6 (correct) ... so it checks out
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