Find the sum (3/7m-3+4n) + (2/7m-2m+6)

(5/7) m + 2n + 3

Step-by-step explanation:

Rewrite 3/7m as (3/7) m for added clarity, also 2/7m as (2/7) m.

Adding (3/7) m and (2/7) m results in (5/7) m.

Next, combine - 3 and 6, which yields 3.

I expected that there'd be only one term in m in both quantities. (3/7) m - 3 + 4n does have only one term, but (2/7) m - 2m + 6) seems to have two m terms. I will assume that you actually meant (2/7) m - 2n + 6).

Combining like terms, we get (5/7) m + 3 + 4n - 2n, or

(5/7) m + 2n + 3