The sum of three different two-digit prime numbers is 79. the largest of the numbers is 43. the difference of the other two is 10. what is the product of the three numbers

Let the number be x, y and 43

y-x=10

thus

y=10+x

the sum off the numbers will be:

x+y+43=79

plugging the values we get:

x + (10+x) + 43=79

solving for x we get:

2x+53=79

2x=79-53

2x=26

x=26/2=13

hence:

y=10+13=23

thus the numbers are 13,23 and 43

the product of the number will be:

13*23*43

=12,857

Answer: 12,857