Find 4 consecutive odd numbers such that the sum of the first and the forth is 27 less than three times the first

Question

Brenton

Mathematics

3 December, 20:52

Find 4 consecutive odd numbers such that the sum of the first and the forth is 27 less than three times the first

+3

Answers (1)

Know the Answer?

Jazlene Mcclure · Answer 1

Hello,

Let's assume

2n-3 the first number

2n-1 the second

2n+1 the third

2n+3 the forth

2n-3+2n+3=3 * (2n-3) - 27

4n=6n-9-27

2n=36

==>2n-3=33

2n-1=35

2n+1=37

2n+3=39

Proof: 33+39=72

3*33-27=72