Recall that the equation for horizontal distance "h" in feet of a projectile with initial velocity v0 and initial angle theta is given by h = (v0^2/16) sin theta cos theta. a.) Assume the initial velocity is 60 (feet/second). What initial angle will you need to ensure that the horizontal distance will be exactly 100 feet? b.) Assume the initial velocity is 60 feet/second. What is the maximum horizontal distance possible and at what angle does this occur?

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Zoe

Mathematics

29 September, 19:16

Recall that the equation for horizontal distance "h" in feet of a projectile with initial velocity v0 and initial angle theta is given by h = (v0^2/16) sin theta cos theta. a.) Assume the initial velocity is 60 (feet/second). What initial angle will you need to ensure that the horizontal distance will be exactly 100 feet? b.) Assume the initial velocity is 60 feet/second. What is the maximum horizontal distance possible and at what angle does this occur?

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Kendall · Answer 1

A

100 = (60^2 / 16) sin theta cos theta

100 = 225 sin theta cos theta

sin theta cos theta = 100/224 = 0.4444

1/2 sin 2theta = 0.4444

sin 2theta = 0.8888

2 * theta = 62.73 degrees

theta = 31.37 degrees