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7 December, 18:34

The length of a rectangular garden is 7 feet longer than its width. If the garden's perimeter is 178 feet what is the area of the garden in square feet.

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  1. 7 December, 18:51
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    Answer:1968ft^2

    Step-by-step explanation:

    Perimeter (p) = 178feet

    P=2L+2w

    178=2L+2w

    178=2 (L+w)

    L+w=178 ➗ 2

    L+w=89 ... (1)

    W+7=L

    L-w=7 ... (11)

    L+w=89 ... (1)

    L-w=7 ... (11)

    Subtract (11) from (1)

    2w=89-7

    2w=82

    w=82 ➗ 2

    w=41 width=41feet

    Substitute w=41 in (11)

    L-w=7

    L-41=7

    L=7+41

    L=48feet

    Area = length x width

    Area=48 x 41

    Area=1968ft^2
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