If the area of a rectangle is 85 square meters, and the width is ten meters

shorter than the length, find the perimeter of the rectangle in meters. Round

your answer to two decimal places.

A) 35.49 meters

B) 21.25 meters

C) 61.95 meters

D) 81.95 meters

E) 41.95 meters

Answer: E.) 41.95m

Step-by-step explanation:

Area (A) = 85 square meters

Length (L) = a

Width (W) = (a - 10) meters

Area of rectangle (A) = Length (L) * Width (W)

85 = a * (a - 10)

85 = a^2 - 10a

a^2 - 10a - 85 = 0

Using quadratic equation solver:

a = 15.488088482 or a = - 5.488088482

Since a cannot be negative, a = 15.49m

Therefore, Length (L) = 15.488m

Width (W) = a - 10 = (15.488 - 10) = 5.488m

Perimeter of rectangle (P):

P = 2 (L + W)

P = 2 (15.488 + 5.488)

P = 2 (20.976)

P = 41.952m

P = 41.95m