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Savannah Huerta
Mathematics
21 August, 07:54
Find the zeros of each function.
f (x) = x^2 + 5x - 6
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Ishaan
21 August, 08:19
0
zeros of function f (x) = x^2 + 5x - 6 is 1 and - 6
Step-by-step explanation:
Let f (x) = x^2 + 5x - 6
To find the Zeros
consider two numbers - 1 and - 6
Let - 1 * 6 = 6
-1 + 6 = 5
f (x) can be written as,
f (x) = x^2 + 5x - 6
f (x) = x^2 - x + 6x - 6
f (x) = x (x - 1) + 6 (x - 1)
f (x) = (x - 1) (x + 6)
Therefore zeros of f (x) = 1 and - 6
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Conner Scott
21 August, 08:21
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x=1 x=-6
Step-by-step explanation:
f (x) = x^2 + 5x - 6
What two number multiply together to give us - 6 and add to give us 5
-1 * 6 = - 6
-1 + 6 = 5
(x-1) (x+6) = 0
Using the zero product property
x-1 = 0 x+6 = 0
x-1+1=0+1 x+6-6=0-6
x=1 x=-6
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