The product of two consecutive odd integers is 195.

Write an equation to model the situation.

A) n (n + 1) = 195

B) n (n + 2) = 195

C) n (n + 3) = 195

D) (n + 1) (n + 2) = 195

You need the odd integers to be separated by 2. One will not work.

If n is odd, n + 1 will be even. You cannot get an exception to that. Try it.

1 is odd but 1 + 1 is even.

n and n + 3 produces 1 odd and 1 even. If n is odd then since 3 is odd when the two are added together, you get an even. Again try it

n = 5

n + 3 = 8

C: is not the answer.

D can't work either. If n is odd then n + 2 will be odd but n + 1 is even.

The Answer is B.

n (n + 2) = 195

n^2 + 2n - 195 = 0

(n - 13) (n + 15)

n can be 13 and n + 2 can be 15

13 * 15 = 195

But here's something you may not know

n can be - 15 and then the other odd number would be - 13