Find three consecutive odd integers who sum is 13 more than twice the largest of the three integers

The integers would be 15, 17, and 19

Step-by-step explanation:

In order to find this, set the smallest equal to x, with the next largest being x + 2 and the largest being x + 4. Now we can write the following equation to solve for the smallest.

x + x + 2 + x + 4 = 2 (x + 4) + 13

3x + 6 = 2x + 21

x + 6 = 21

x = 15

Now since the first is 15, we know the next two are 17 and 19