Find the numerical value of x=4 and y=5. 3x^2+6y=

Question

Jerry

Mathematics

25 November, 07:53

Find the numerical value of x=4 and y=5. 3x^2+6y=

+4

Answers (2)

Know the Answer?

Caprice · Answer 1

174

Step-by-step explanation:

3x^2+6y

3 (4) ^2+6 (5)

12^2+30

144+30

174

Pugsley · Answer 2

78.

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Why?

Replace the variables for their respective values.

3 (4) ^2 + 6 (5)

Then solve for 4^2.

3 (16) + 6 (5)

Now, solve the multiplication.

48 + 30

Finally, solve the addition.

78

78 is your answer.