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22 November, 22:33

Solve for K, the constant of variation, in a joint variation problem where y=520, x=5, z=6.5. Solution is?

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  1. 22 November, 23:02
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    K = 676

    Step-by-step explanation:

    When y is directly proportional to x and inversely poportional to z

    We have

    y = kx/z

    When y = 520

    x = 5

    z = 6.5

    K = ?

    We have

    520 = k x 5/6.5

    Cross multiply

    520 x 6.5 = 5k

    3380 = 5k

    Divide both sides by 5

    3380/5 = 5k/5

    676 = k

    k = 676
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