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19 February, 01:10

The perimeter of a rectangle is 400 meters. The length is 15 meters less than the width. Find the length and width

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  1. 19 February, 01:36
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    Ok ... Perimeter is = 2l + 2w

    w being width and l being length.

    We know that perimeter is equal to 400 so

    400 = 2l + 2w

    The length is 15 meters less than the width, so in notations, l = w - 15

    We can substitute than in the equation to get 2 (w-15) + 2w = 400

    Expanding will give 2w - 30 + 2w = 400

    Solving w gives w = 430/4 = 107.5 meters

    Substituting in original equation for w to find l, 400 = 2l + 2 (107.5)

    400 = 2l + 215

    2l = 185

    l = 92.5 cm

    Or you can just use the question to know that the length is 15 times less than the width, so 107.5 - 15 = 92.5

    Length = 92.5 cm

    Width = 107.5 cm
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