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8 April, 01:01

What are the roots of the polynomial equation x^3-7x=6x-12?

a. - 6, 6

b. - 4, 1, 3

c. - 3, - 1, 4

d. 1, 3

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Answers (1)
  1. 8 April, 01:12
    0
    Hello,

    Answer B

    P (x) = x^3-13x+12

    P (1) = 1-13+12=0 = = >1 is root

    P (3) = 3^3-13*3+12=0 = = >3 is root

    P (-4) = (-4) ^3-13 * (-4) + 12=0 is root

    P (x) = (x-1) (x-3) (x+4)
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