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Bullock
Mathematics
27 May, 13:58
What is the solution to the equation x2 + 6x=40
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Isaac Price
27 May, 14:01
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x² + 6x = 40 Subtract 40 on both sides to get the equation equal to 0.
x² + 6x - 40 = 0
Now you need to factor the equation. To do so, you find the factors of 40 that add or subtract to 6.
Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40
[1 * 40, 2 * 20, 4 * 10, 5 * 8]
4 and 10 subtracts to 6.
Instead of 6x:
x² + 6x - 40 = 0
You can replace 6x with:
x² - 4x + 10x - 40 = 0 [this is because the sum of - 4x and 10x is 6x]
Now factor the equation separately. Factor out x in (x² - 4x), and factor out 10 in (10x - 40)
x (x - 4) + 10 (x - 4) = 0 Factor out (x - 4)
(x - 4) (x + 10) = 0
x - 4 = 0 Add 4 on both sides
x = 4
x + 10 = 0 Subtract 10 on both sides
x = - 10
x = 4, x = - 10
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Brighton
27 May, 14:20
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x=10 x=-4
Step-by-step explanation:
x^2 + 6x = 40
subtract 40 from each side
x^2 + 6x - 40 = 0
what numbers multiply to - 40 and add to 6
-10 * 4 = - 40 - 10 + 4 = 6
(x-10) (x+4) = 0
using the zero product property
x-10 = 0 x+4 = 0
x=10 x=-4
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