Megan started biking to the internet cafe traveling 9 mph, after some time the bike got a flat so Megan walked the rest of the way, traveling 7 mph. If the total trip to the internet cafe took 9 hours and it was 75 miles away, how long did Megan travel at each speed

Question

Essence Gibbs

Mathematics

6 May, 04:56

Megan started biking to the internet cafe traveling 9 mph, after some time the bike got a flat so Megan walked the rest of the way, traveling 7 mph. If the total trip to the internet cafe took 9 hours and it was 75 miles away, how long did Megan travel at each speed

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Answers (2)

Know the Answer?

Georgia Duarte · Answer 1

Answer: d=54 miles

Step-by-step explanation:

We let the distance megan covered = d

And the distance she walked to the cafe will be:

75 - d

Therefore

d/9 + (75 - d) / 7 = 9

L. c. m is 63

7d+9 (75-d) = 63*9

7d+675-9d=567

-2d=567-675

d=108/2

d=54

d=54 miles

Greta Molina · Answer 2

Megan travelled at 9mph for 6 hours and 7mph for 3 hours

Step-by-step explanation:

Speed = distance / time

Speed*time = distance

Assuming that Megan travelled x hours at 9mph

(9*x) + (7 * (9-x)) = 75

x = 6 hours

So Megan travelled at 9mph for 6 hours and 7mph for 3 hours