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14 July, 07:51

On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = - 1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?

That turned out to be much harder-as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = - 80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)

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  1. 14 July, 08:03
    0
    if i see them it my be 5x6x7=76 6 (*) 665_+65x673 then add those toether then sub em 56-78-463=738
  2. 14 July, 08:05
    0
    Well, lets see∉ if you add theose numbers togetherФ it maybe it he answe ris 4=67 * 64 - --4 67x54 5xe4t4 6x

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