A cyclist bikes at a constant speed for 22 miles. He then returns home at the same speed but takes a different route. His return trip takes one hour longer and is 27 miles. Find his speed

How concerned are you with how to get the answer?

Because I know the answer is 5 miles per hour

22/5 = 4.4 hours

27/5 = 5.4 hours

Alright this is how you solve it

Distance over time equals speed

So 22/y=x and 27/y+1=x

Start by solving for time by having these two equations equal each other

22/y=27/y+1

Cross multiply to get

22 (y+1) = 27y

22y+22=27y

Isolate Y

5y=22

Y=4.4

Now solve for X which is the speed, you can plug in Y to either of the two equations

22/4.4=x

X=5 miles per hour