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10 October, 20:12

Find the 4th term of the expansion of (2a-b) ^7

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  1. 10 October, 20:21
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    -560a^4b^3.

    Step-by-step explanation:

    For a binomial expansion:

    (r + 1) th term of (a + b) ^n = nCr a^ (n-r) b^r.

    So the 4th term of (2a - b) ^7

    = (3 + 1) th term = 7C3 (2a) ^ (7-3) (-b) ^3

    = 35 * 16a^4 * - b^3

    = - 560a^4b^3 (answer).
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