If a rectangle has an area of 30 square meters and a perimeter of 34 meters. what is the dimensions of the rectangle?

P=2 (L+W) and P=34 so

2 (L+W) = 34

L+W=17 so we can say

L=17-W

A=LW using L from above

A = (17-W) W

A=17W-W^2 and A=30 so

30=17W-W^2

W^2-17W+30=0

W^2-2W-15W+30=0

W (W-2) - 15 (W-2) = 0

(W-15) (W-2) = 0

So the dimensions of the rectangle are 15 meters by 2 meters.