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30 August, 02:33

A chemist needs 90 milliliters of a 25% solution but has only 16% and 43% solutions available

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  1. 30 August, 02:43
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    Let f be amount of 43% and s be amount of 16% ...

    s+f=90, f=90-s

    (.16s+.43f) / 90=.25 using f found above we get:

    (.16s+.43 (90-s)) / 90=.25

    .16s+38.7-.43s=22.5

    -.27s=-16.2

    s=60, and since f=90-s, f=30

    So the chemist will need to mix 60ml of 16% solution with 30ml of 43% solution to create 90ml of a 25% solution.
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