Tom has been playing on the school bowling team. In his first year as a freshman, his bowling average was 180. He had been bowling at this time for two years. In his second year as a sophomore, Tom's bowling average was 225. What is the percentage change in Tom's bowling average? (hint: divide something by 180)

Question

Snowy

Mathematics

1 December, 20:35

Tom has been playing on the school bowling team. In his first year as a freshman, his bowling average was 180. He had been bowling at this time for two years. In his second year as a sophomore, Tom's bowling average was 225. What is the percentage change in Tom's bowling average? (hint: divide something by 180)

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Answers (1)

Know the Answer?

Darwin Lam · Answer 1

0.000025

Step-by-step explanation:

the difference between225-180=45

so the percentage = 45*100/100

=0.45%

as the instruction say=0.45%/180

=0.0045/180

=45/1800000

=0.000025