Ask Question
27 December, 15:44

Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by (x-2) ^2=10 (y-3), where x and y are measured in inches. Where is the focus of the flashlight?

+3
Answers (1)
  1. 27 December, 16:13
    0
    F (2, 11/2)

    Step-by-step explanation:

    The expression:

    (x-2) ² = 10 (y - 3)

    can be rewritten in the vertex form as follows:

    (x-2) ² = 10y - 30

    (x-2) ² + 30 = 10y

    1/10 (x-2) ² + 3 = y

    General vertex form is:

    y = a (x-h) ² + k

    then, the vertex is locate at (h, k). In this case the vertes is (2, 3), and a = 1/10

    The focus of a parabola is located ar F (h, k+p), where p = 1 / (4a). Replacing into these equations:

    p = 1 / (4*1/10) = 5/2

    F (2, 3+5/2) = F (2, 11/2)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Fabio is designing a flashlight that uses a parabolic reflecting mirror and a light source. The shape of the mirror can be modeled by (x-2) ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers