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Maddison Santiago
Mathematics
12 December, 16:14
How do you solve the simultaneous equations?
y = x + 4
y = 2x² + 3x - 1
+5
Answers (
1
)
Jair Mcgee
12 December, 16:17
0
(1.16, 5.16) and (-2.16, 1.84) to the nearest hundredth.
Step-by-step explanation:
By substitution. You substitute y = x + 4 into the second equation:
x + 4 = 2x^2 + 3x - 1
2x^2 + 2x - 5 = 0
x = [ - 2 + / - sqrt (2^2 - 4*1*-5) ] / 2*2
= - 1/2 + / 1 sqrt 24/4
= 1.158, - 2.158
When x = 1.158, y = 1.158 + 4 = 5.158
When x = - 2.158, y = - 2.158 + 4 = 1.842.
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