Solve 4y^2-16y+16=0.

Answer: y=2

Step-by-step explanation:

4y^2-16y+16=0 To "solve" means to find the value of x for which this equation is true.

y^2 - 4y + 4 = 0 [divide by 4; this is the same equation]

(y-2) (y-2) = 0 [You may factor or use the quadratic equation]

y=2 and y=2 [the same answer]

Check:

Does (2) 2 - 4 (2) + 4 = 0?

4 - 8 + 4 = 0?

0 = 0? yes

y=2

Step-by-step explanation:

1) factor the equation

2) set factors equal to 0