Find two consequtive odd integers such that 4 times the first integer is 29 less than 7 times the second

Odd integers are 2 apart

so they are x and x+2

the first is x and the 2nd is x+2

4 times the first is 29 less than 7 times the 2nd

4x=-29+7 (x+2)

solve

distribute

4x=-29+7x+14

4x=-15+7x

minus 7x both sides

-3x=-15

divide both sides by - 3

x=5

x+2=7

the numbers are 5 and 7

Let the consecutive odd integers be x, x+2.

Given,

4x = 7 (x + 2) - 29

4x = 7x + 14 - 29

3x = 15

x = 5

Thus, the consecutive odd integers are 5 and 7.